document.write( "Question 1179017: Write the equation given information:
\n" ); document.write( "Hole when x=-2
\n" ); document.write( "Horizontal asymptote y=0
\n" ); document.write( "Vertical asymptote x=0, x=-5
\n" ); document.write( "x-intercept (3,0)
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Algebra.Com's Answer #808509 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Write the equation given information:
\n" ); document.write( "Hole when \"x=-2\"
\n" ); document.write( "Horizontal asymptote \"y=0\"
\n" ); document.write( "Vertical asymptote \"x=0\", \"x=-5\"
\n" ); document.write( "x-intercept (\"3\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "A rational function is one such that \"f%28x%29=P%28x%29%2FQ%28x%29\", where \"Q%28x%29\"\"0\"; the domain of a rational function can be calculated.\r
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\n" ); document.write( "\n" ); document.write( "given: hole when \"x=-2\"
\n" ); document.write( "The hole means that the numerator and denominator are both zero at \"x=-2\"
\n" ); document.write( "-> numerator P(x) must have \"x-%28-2%29=x%2B2\" as a factor\r
\n" ); document.write( "\n" ); document.write( "\"P%28x%29%2FQ%28x%29+=%28x%2B2%29+%2F%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "given horizontal asymptote \"y=0\"\r
\n" ); document.write( "\n" ); document.write( " If the degree of the numerator is less than the degree of the denominator, then the horizontal asymptote is always the \"x\" axis, i.e. the line \"y+=+0\"\r
\n" ); document.write( "\n" ); document.write( "=>so, \"P%28x%29+=%28x%2B2%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Vertical asymptotes occur at singularities of a rational function, or points at which the function is not defined. They only occur at singularities where the associated linear factor in the denominator remains after cancellation.\r
\n" ); document.write( "\n" ); document.write( "since given vertical asymptote \"x=0\", \"x=-5\", you have denominator\r
\n" ); document.write( "\n" ); document.write( "\"Q%28x%29=%28x-0%29%28x-%28-5%29%29=x%28x%2B5%29=x%5E2%2B5x\"\r
\n" ); document.write( "\n" ); document.write( "given x-intercept (\"3\",\"0\"), so numerator have \"%28x-3%29\"\r
\n" ); document.write( "\n" ); document.write( "so , your function is:\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28%28x%2B2%29%28x-3%29%29+%2F%28%28x%2B2%29%28x%5E2%2B5x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x%5E2+-+x+-+6%29+%2F%28x%5E3+%2B+7x%5E2+%2B+10x%29\"\r
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