document.write( "Question 1178993: Solve the following simultaneous equations: 3𝑥^2 − 2𝑥𝑦 + 𝑦^2 − 1 = 0 and
\n" ); document.write( "𝑥 =(2𝑦+1)/𝑥
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Algebra.Com's Answer #808485 by mananth(16946)\"\" \"About 
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3𝑥^2 − 2𝑥𝑦 + 𝑦^2 − 1 = 0 and \r
\n" ); document.write( "\n" ); document.write( "𝑥 =(2𝑦+1)/𝑥
\n" ); document.write( "x^2 = (2y+1)\r
\n" ); document.write( "\n" ); document.write( "3𝑥^2 − 2𝑥𝑦 + 𝑦^2 − 1 = 0
\n" ); document.write( "3(2y+1)^2 -2y(2y+1) -1=0
\n" ); document.write( "3(4y^2+4y+1) -4y^2-2y -1=0
\n" ); document.write( "12y^2+12y +3 -4y^2-2y-1=0
\n" ); document.write( "8y^2+10y+2=0
\n" ); document.write( "8y^2+8y+2y+2=0
\n" ); document.write( "8y(y+1) +2(y+1)=0
\n" ); document.write( "(8y+2)(y+1)=0
\n" ); document.write( "y=-1/4 or y=-1
\n" ); document.write( "Plug the values of y in x^2=(2y+1)
\n" ); document.write( "and get values of x for each y.\r
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