document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110850>Question 110850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I still didn't get an answer for this one.  It's not a typo, as far as I know, but I can't get started on it.\r<BR>\n" );
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document.write( "Solve the following exponential equation:\r<BR>\n" );
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document.write( "49 over(/) 1-1e^3x = 68\r<BR>\n" );
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document.write( "If there's a typo, it could be 1-1e^3x is supposed to be read 1-1e_3x, but the 3x definitely looks like a little exponent and not a base. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80846 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying by (1-1e^3x) and dividing by 68 gives 49/68=1-1e^3x\r<BR>\n" );
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document.write( "subtracting 1 and multiplying by -1 gives 19/68=e^3x\r<BR>\n" );
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document.write( "taking the natural log gives ln(19/68)=3x </SPAN>\n" );
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