document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1178956>Question 1178956</A>: <I><SPAN STYLE=\"word-break: break-all;\"> https://gyazo.com/5dea05c1d7b581a2db660b0f832c8345 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #808431 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=808431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=(2x-3)/(x-2)<BR>\n" );
document.write( "at infinity (-) the function is +2<BR>\n" );
document.write( "at x=3/2 the function is 0<BR>\n" );
document.write( "at x=2, the function is undefined, and it is negative infinity from the left and positive infinity from the right<BR>\n" );
document.write( "at infinity (+) the function is +2.<BR>\n" );
document.write( "so from (-oo, 3/2) the function is decreasing from 2 to 0<BR>\n" );
document.write( "from ((3/2) to 2), the function is decreasing from 0 to -oo.<BR>\n" );
document.write( "from (2, +oo), it is again decreasing.<BR>\n" );
document.write( "There is a discontinuity at x=2.<BR>\n" );
document.write( "There is no place where it is continuous and increasing.\r<BR>\n" );
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