document.write( "Question 110851: Jim can fill a pool carrying bucks of water in 30 minutes. Sue can do the same job in 45 minutes. Tony can do the same job in 1 ½ hours. How quickly can all three fill the pool together? \n" ); document.write( "

Algebra.Com's Answer #80843 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Jim can fill a pool carrying buckets of water in 30 minutes. Sue
\n" ); document.write( " can do the same job in 45 minutes. Tony can do the same job in
\n" ); document.write( " 1 ½ hours. How quickly can all three fill the pool together?
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\n" ); document.write( "Let t = time required if they work together
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\n" ); document.write( "Let 1 = the full pool
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\n" ); document.write( "Convert 1.5 hrs to minutes: 90 min
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\n" ); document.write( "A simple equation:
\n" ); document.write( " $\"t%2F30\"$ + $\"t%2F45\"$ + $\"t%2F90\"$ = 1
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\n" ); document.write( "Multiply equation by 90, this get rid of the denominators;
\n" ); document.write( "You then have
\n" ); document.write( "3t + 2t + t = 90
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\n" ); document.write( "6t = 90
\n" ); document.write( "t = 90/6
\n" ); document.write( "t = 15 minutes working together:
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\n" ); document.write( "Check solution:
\n" ); document.write( "15/30 + 15/45 + 15/90 =
\n" ); document.write( "1/2 + 1/3 + 1/6 =
\n" ); document.write( "3/6 + 2/6 + 1/6 = 1\r
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