document.write( "Question 1178952: https://gyazo.com/476623f75a5bf00a7c1a4802c602403e \n" ); document.write( "
Algebra.Com's Answer #808426 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"y=%283x%5E2-4x%29%2F%282x%2B1%29\" tangent at\"+x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "first find a slope and tangent point\r
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\n" ); document.write( "\n" ); document.write( "\"y\"'\"%28x%29+=+%286x%5E2+%2B+6+x+-+4%29%2F%282+x+%2B+1%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "substitute \"x=-1\"\r
\n" ); document.write( "\n" ); document.write( "\"y\"'\"%28-1%29+=%286%28-1%29%5E2+%2B+6+%28-1%29+-+4%29%2F%282+%28-1%29+%2B+1%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"y\"'\"%28-1%29+=+-4\"->Note this only tells us the slope of the line, not the equation for the line itself.\r
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\n" ); document.write( "\n" ); document.write( "since the line is tangent to the function at \"+x=-1\", by finding the \"y\"-coordinate we would possess a set of coordinates and a slope, allowing us to use point-slope form\r
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\n" ); document.write( "\n" ); document.write( "\"y=%283%2A%28-1%29%5E2-4%2A%28-1%29%29%2F%282%2A%28-1%29%2B1%29+=-7\"\r
\n" ); document.write( "\n" ); document.write( "tangent point is (\"-1\",\"-7\") and slope is\"m=+-4\"\r
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\n" ); document.write( "\n" ); document.write( "use point-slope form\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y-%28-7%29=-4%28x-%28-1%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2B7=-4%28x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-4x-4-7\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-4x-11\"\r
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