document.write( "Question 1178926: A shipment of 10 TV sets contains 2 units that are defective. In how many ways can 3 TV sets be inspected such that:
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document.write( "a. no defective TV set is included?
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document.write( "b. both defective TV sets are included for inspection?
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document.write( "c. only one of the defective TV sets is included?\r
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Algebra.Com's Answer #808391 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "a. no defective TV set is included --> choose 0 of the 2 bad TVs and 3 of the 8 good TVs: C(2,0)*C(8,3) \n" ); document.write( "b. both defective TV sets are included for inspection --> choose 2 of the 2 bad TVs and 1 of the 8 good TVs: C(2,2)*C(8,1) \n" ); document.write( "c. only one of the defective TV sets is included --> choose 1 of the 2 bad TVs and 2 of the 8 good TVs: C(2,1)*C(8,2) \n" ); document.write( "If that is not enough of an answer for you, re-post the question telling us what it is about the problem that you are having trouble with. \n" ); document.write( " \n" ); document.write( " |