document.write( "Question 1178895: construct a 99% confidence interval estimate for a population of 50, a standard deviation of .02 and a sample mean of .995\r
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Algebra.Com's Answer #808351 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi\r\n" );
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document.write( "ME =,  = .0028\r\n" );
document.write( "n > 40 and population σ = .02   µ =.995\r\n" );
document.write( " 99% confidence interval estimate  \r\n" );
document.write( "ME = = .0072\r\n" );
document.write( ".995- .007 <  < .995 + .007\r\n" );
document.write( "CI: (.988, 1.002)\r\n" );
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document.write( "95% interval:\r\n" );
document.write( "ME = = .0055 \r\n" );
document.write( ".995 - .0055<  < .995 + .0055\r\n" );
document.write( "CI: (.9895, 1.0055)\r\n" );
document.write( "CI  is wider at 99%\r\n" );
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document.write( "Wish You the Best in your Studies.\r\n" );
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