document.write( "Question 1178882: find the slope-intercept equation that passes through (-1,2) and is perpendicular to the line with the equation 6y-x=12 \n" ); document.write( "
Algebra.Com's Answer #808315 by mananth(16946)\"\" \"About 
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\n" ); document.write( "6y-x =12\r
\n" ); document.write( "\n" ); document.write( "6y=x+12
\n" ); document.write( "y= (1/6)x +12\r
\n" ); document.write( "\n" ); document.write( "slope = 1/2\r
\n" ); document.write( "\n" ); document.write( "Slope of perpendicular line will be negative reciprocal of (1/6)\r
\n" ); document.write( "\n" ); document.write( "slope = -6\r
\n" ); document.write( "\n" ); document.write( "This line with slope -6 passes through -1 ,2
\n" ); document.write( "plug these values to get value of b\r
\n" ); document.write( "\n" ); document.write( "y=mx+b\r
\n" ); document.write( "\n" ); document.write( "2= -6*-1 +b
\n" ); document.write( "2+6=b
\n" ); document.write( "b=-4\r
\n" ); document.write( "\n" ); document.write( "The required equation is y = -6x -4
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