document.write( "Question 110797: Solve.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the width of the rectangle.
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Algebra.Com's Answer #80822 by checkley71(8403)\"\" \"About 
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L=2W+8
\n" ); document.write( "2L+2W=34
\n" ); document.write( "2(2W+8)+2W=34
\n" ); document.write( "4W+16+2W=34
\n" ); document.write( "6W=34-16
\n" ); document.write( "6W=18
\n" ); document.write( "W=18/6
\n" ); document.write( "W=3 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=2*3+8
\n" ); document.write( "L=6+8
\n" ); document.write( "L=14 ANSWER.
\n" ); document.write( "PROOF.
\n" ); document.write( "2*14+2*3=34
\n" ); document.write( "28+6=34
\n" ); document.write( "34=34\r
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