document.write( "Question 110816: Solve.\r
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\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 34 in., find the width of the rectangle.
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Algebra.Com's Answer #80820 by edjones(8007)\"\" \"About 
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Let L=length, w=width
\n" ); document.write( "L=2w+8
\n" ); document.write( "2L+2w=P
\n" ); document.write( "2(2w+8)+2w=34
\n" ); document.write( "4w+16+2w=34
\n" ); document.write( "6w+16-16=34-16
\n" ); document.write( "6w=18
\n" ); document.write( "6w/6=18/6
\n" ); document.write( "w=3
\n" ); document.write( "L=2*3+8
\n" ); document.write( "L=14
\n" ); document.write( "Ed\r
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