document.write( "Question 961723: A vending machine has $6.30 in it. There are 52 coins total and the machine only accepts nickels, dimes, and quarters. There are five more dimes than nickels. How many of each coin are in the machine. \n" ); document.write( "
Algebra.Com's Answer #808182 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "A vending machine has $6.30 in it. There are 52 coins total and the machine only accepts nickels,
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\n" ); document.write( "\n" ); document.write( "            It is a typical problem to be solved using only one single unknown and only one single equation.\r
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document.write( "Let x be the number of nickels.\r\n" );
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document.write( "Then the number of dimes is (x+5), according to the condition.\r\n" );
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document.write( "The quarters are the rest coins, and their number is  (52-x-(x+5)) = (47-2x).\r\n" );
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document.write( "Having it, you write the total money equation\r\n" );
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document.write( "    5x + 10(x+5) + 25*(47-2x) = 630   cents.\r\n" );
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document.write( "Simplify and solve\r\n" );
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document.write( "    5x + 10x + 50 + 25*47 - 50x = 630\r\n" );
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document.write( "         -35x                   = 630 - 50 - 25*47 = -595\r\n" );
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document.write( "            x                                      = \"%28-595%29%2F%28-35%29\" = 17.\r\n" );
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document.write( "ANSWER.  17 nickels, 22 dimes and the rest 52 - 17-22 = 13  coins are quaters.\r\n" );
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document.write( "CHECK.  17*5 + 22*10 + 13*25 = 630 cents, in total.    ! Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "like  @josgarithmetic or  @Penguin,  may think differently . . . \r
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