Algebra.Com's Answer #808158 by ikleyn(52786)  You can put this solution on YOUR website! .\r \n" );
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document.write( " Let me show you how to solve it without using equations.\n" );
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document.write( "We have a parabola, and its ordinate y at x= 1 is the same as the ordinate y at x= 3.\r\n" );
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document.write( "It means that the parabola's symmetry axis is x= 2 half way between x= 1 and x= 3.\r\n" );
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document.write( "Hence, the parabola has a vertex at x= 10, and the vertex form equation is\r\n" );
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document.write( " y = a*(x-2)^2 + 10.\r\n" );
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document.write( "where \"a\" is a coefficient, now unknown.\r\n" );
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document.write( "To find \"a\", substitute x= 3 into the vertex form equation.\r\n" );
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document.write( "You will get then\r\n" );
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document.write( " 9 = a*(3-2)^2 + 10, or\r\n" );
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document.write( " a*1^2 = 9 - 10\r\n" );
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document.write( " a = -1.\r\n" );
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document.write( "So, the vertex form equation is\r\n" );
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document.write( " y = -(x-2)^2 + 10.\r\n" );
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document.write( "Rewrite it in the general form\r\n" );
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document.write( " y = -(x^2 - 4x + 4) + 10 = -x^2 + 4x + 6.\r\n" );
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document.write( "Thus a= -1, b= 4, c= 6.\r\n" );
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document.write( " P L O T\r\n" );
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document.write( " Plot y = = \r\n" );
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document.write( "Solved.\r \n" );
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