document.write( "Question 962309: Given 2 quarters and 3 dimes how many different amounts of money can be created using 1 or more coins \n" ); document.write( "

Algebra.Com's Answer #808156 by ikleyn(52787) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "how many = 3*4 - 1 = 12 - 1 = 11. ANSWER\r
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Explanation

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\n" ); document.write( "\n" ); document.write( "3 opportunity for quarters (0, 1, 2)\r
\n" ); document.write( "\n" ); document.write( "and 4 opportunity for dimes (0, 1, 2, 3).\r
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\n" ); document.write( "\n" ); document.write( "So the product 3*4 = 12 is the number of all different possible combinations (pairs (q,d) ).\r
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\n" ); document.write( "\n" ); document.write( "Minus the degenerated case (q,d) = (0,0) gives finally the answer 12-1 = 11.\r
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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