document.write( "Question 965463: if Barbara has 20 coins consisting of nickels and dimes. If the nickels were dines and the dimes were nickels she would have 30 cents more than she has now how many dimes did she have to begin with? \n" ); document.write( "
Algebra.Com's Answer #808096 by CubeyThePenguin(3113)\"\" \"About 
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n = number of nickels
\n" ); document.write( "d = number of dimes\r
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\n" ); document.write( "\n" ); document.write( "n + d = 20
\n" ); document.write( "5n + 10d + 30 = 10n + 5d ---> 30 = 5n - 5d\r
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\n" ); document.write( "\n" ); document.write( "n + d = 20
\n" ); document.write( "n - d = 6
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\n" ); document.write( "2n = 26 ---> n = 13\r
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\n" ); document.write( "\n" ); document.write( "number of dimes = d = 7
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