document.write( "Question 969659: A man has 20 coins in his pocket consisting of 5 peso, 10 peso and 1 peso coins. There are an equal number of ones and fives among them. He has 88 pesos in all. How many coins of each denomination are there? \n" ); document.write( "
Algebra.Com's Answer #808045 by CubeyThePenguin(3113)\"\" \"About 
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(repeat question)\r
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\n" ); document.write( "\n" ); document.write( "p = number of 1 peso coins
\n" ); document.write( "n = number of 5 peso coins
\n" ); document.write( "d = number of 10 peso coins\r
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\n" ); document.write( "\n" ); document.write( "p = n
\n" ); document.write( "p + n + d = 20
\n" ); document.write( "p + 5n + 10d = 88\r
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\n" ); document.write( "\n" ); document.write( "2n + d = 20
\n" ); document.write( "6n + 10d = 88\r
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\n" ); document.write( "\n" ); document.write( "20n + 10d = 200
\n" ); document.write( "-(6n + 10d = 88)
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\n" ); document.write( "14n = 112
\n" ); document.write( "n = 8\r
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\n" ); document.write( "\n" ); document.write( "--> 8 1-peso coins, 8 5-peso coins, 4 10-peso coins.
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