document.write( "Question 969659: A man has 20 coins in his pocket consisting of 5 peso, 10 peso and 1 peso coins. There are an equal number of ones and fives among them. He has 88 pesos in all. How many coins of each denomination are there? \n" ); document.write( "
Algebra.Com's Answer #808045 by CubeyThePenguin(3113) You can put this solution on YOUR website! (repeat question)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = number of 1 peso coins \n" ); document.write( "n = number of 5 peso coins \n" ); document.write( "d = number of 10 peso coins\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = n \n" ); document.write( "p + n + d = 20 \n" ); document.write( "p + 5n + 10d = 88\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2n + d = 20 \n" ); document.write( "6n + 10d = 88\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20n + 10d = 200 \n" ); document.write( "-(6n + 10d = 88) \n" ); document.write( "--------------------- \n" ); document.write( "14n = 112 \n" ); document.write( "n = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--> 8 1-peso coins, 8 5-peso coins, 4 10-peso coins. \n" ); document.write( " |