document.write( "Question 110815: Please show me how to do this. Thank you in advance for your help.\r
\n" ); document.write( "\n" ); document.write( "Factor completely:
\n" ); document.write( "x3 – 26x2 + 48x
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Algebra.Com's Answer #80799 by MathLover1(20850)\"\" \"About 
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\"x%5E3\"–\"26%2Ax%5E2\"+ \"48%2Ax\"……….factor out common factor \"x\" \r
\n" ); document.write( "\n" ); document.write( "= \"x%28+x%5E2+-+26x+%2B+48%29\"………now replace \"-+26x\" with the two numbers that multiply to \"48\" and add to \"-26\", which are: \"-2\" and \"-24\")\r
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\n" ); document.write( "\n" ); document.write( "= \"x%28+x%5E2+-+2x+-+24x+%2B+48%29\"………inside parentheses group the first two terms together and the last two terms together like this: \"%28+x%5E2+-+2x%29+%2B+%28-+24x+%2B+48%29\"\r
\n" ); document.write( "\n" ); document.write( "Then we will have:\r
\n" ); document.write( "\n" ); document.write( "= \"x%28%28+x%5E2+-+2x%29+%2B+%28-+24x+%2B+48%29%29\"……… Factor a \"1x\" out of the first group and factor a \"-24\" out of the second group.\r
\n" ); document.write( "\n" ); document.write( "= \"x%281x%28+x+-+2%29+-+24%28x+-+2%29%29\"……… now since we have a common term \"x+%96+2\" we can combine the two terms\r
\n" ); document.write( "\n" ); document.write( "= \"x%28+x+-+2%29+%28x+-+24%29\"………\r
\n" ); document.write( "\n" ); document.write( "So the quadratic \"x%5E3\" – \"26%2Ax%5E2\" +\"+48%2Ax\" factors to \"x%28+x+-+2%29+%28x+-+24%29\"
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