document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1138521>Question 1138521</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ben was describing his coin collection to his friends. He said I have 1.45 pesos more in 5 centavos (nickels) than in 10 centavos (dimes). Ii I had two 5 centavos (nickels) less, I would have 5 times as many 5 centavo (nickels) as 10 centavos (dimes). How many coins of each kind does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807968 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n = number of nickels<BR>\n" );
document.write( "d = number of dimes\r<BR>\n" );
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document.write( "1.45/0.05 = 29<BR>\n" );
document.write( "n = d/2 + 29\r<BR>\n" );
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document.write( "n - 2 = 5d ---> n = 5d + 2\r<BR>\n" );
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document.write( "Set the equations equal to each other.\r<BR>\n" );
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document.write( "d/2 + 29 = 5d + 2<BR>\n" );
document.write( "27 = 9d/2<BR>\n" );
document.write( "d = 6\r<BR>\n" );
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document.write( "Ben has 6 10-centavo coins and 32 5-centavo coins. </SPAN>\n" );
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