document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=989548>Question 989548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a newspaper carrier has $2.60 in change. He has four more quarters than dimes but three times as many nickels as quarters. How many coins of each type does he have </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807956 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n = number of nickels<BR>\n" );
document.write( "d = number of dimes<BR>\n" );
document.write( "q = number of quarters\r<BR>\n" );
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document.write( "5n + 10d + 25q = 260<BR>\n" );
document.write( "q = d + 4<BR>\n" );
document.write( "n = 3q\r<BR>\n" );
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document.write( "Write everything in terms of d.\r<BR>\n" );
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document.write( "5(3(d + 4)) + 10d + 25(d + 4) = 260<BR>\n" );
document.write( "15d + 60 + 10d + 25d + 100 = 260<BR>\n" );
document.write( "50d + 160 = 260<BR>\n" );
document.write( "d = 2\r<BR>\n" );
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document.write( "The news carrier has 18 nickels, 2 dimes, and 6 quarters. </SPAN>\n" );
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