document.write( "Question 1178402: a cylindrical container tank, lying horizontally, 0.90 m. in diameter and 3m long is filled to a depth of 0.60m. how many gallons of water does it contain if one cubic meter is 265 gallons. \n" ); document.write( "
Algebra.Com's Answer #807920 by htmentor(1343)\"\" \"About 
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Refer to the drawing of the cross-section of the pipe. The radius, R of the
\n" ); document.write( "pipe is 0.9/2. The size of the angle BAC is A = 2*acos(0.15/R), and the area of
\n" ); document.write( "the sector subtended by this angle is As = A*R^2/2
\n" ); document.write( "If we subtract the area of the triangle ABC from As, this will give us the area
\n" ); document.write( "of the empty space
\n" ); document.write( "The cross sectional area of the liquid in the pipe will be the total cross
\n" ); document.write( "sectional area minus the area of empty space
\n" ); document.write( "The area of triangle ABC = At = 0.15*sqrt(0.45^2 - 0.15^2)
\n" ); document.write( "Putting in all the numbers we have As = 2.46191*0.45^2/2 = 0.2493 and
\n" ); document.write( "At = 0.0636
\n" ); document.write( "Thus the area of liquid is pi*0.45^2 - (0.2493 - 0.0636) -> 0.4505
\n" ); document.write( "Finally the volume is the area times the length:
\n" ); document.write( "V = 0.4506*3 = 1.3516 m^3 = 358.18 gallons
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