document.write( "Question 1178511: A plate made from a rectangular sheet of metal x metres by y metres has one corner \"rounded\" to a quadrant of a circle with radius r.
\n" ); document.write( "Show that r= 2* sqrt xy-A/4-pi, where A is the area of the \"finished\" plate, given that r>0.
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Algebra.Com's Answer #807906 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"Total+area+=+r%28x-r%29+%2B+x%28y-r%29+%2B+%28pi%2F4%29+r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "A= xr - r^2 +xy -xr +(pi/4) r^2\r
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\n" ); document.write( "\n" ); document.write( "A = xy -r^2 +(pi/4)r^2\r
\n" ); document.write( "\n" ); document.write( "A = xy -r^2 (1-(pi/4))\r
\n" ); document.write( "\n" ); document.write( "A= xy -r^2 ( (4-pi)/4))
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\n" ); document.write( "\"r%5E2+%28+%284-pi%29%2F4%29%29+=xy-A\"\r
\n" ); document.write( "\n" ); document.write( "\"r%5E2+=+%28xy-A%29%2F%28%28%284-pi%29%2F4%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r%5E2+=+4%2A%28xy-A%29+%2F+%284-pi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r=+2%2A+sqrt%28%28xy-A%29%2F%284-pi%29%29\"\r
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