document.write( "Question 1178511: A plate made from a rectangular sheet of metal x metres by y metres has one corner \"rounded\" to a quadrant of a circle with radius r.
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document.write( "Show that r= 2* sqrt xy-A/4-pi, where A is the area of the \"finished\" plate, given that r>0. \n" );
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Algebra.Com's Answer #807906 by mananth(16946)![]() ![]() You can put this solution on YOUR website! ![]() \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A= xr - r^2 +xy -xr +(pi/4) r^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A = xy -r^2 +(pi/4)r^2\r \n" ); document.write( "\n" ); document.write( "A = xy -r^2 (1-(pi/4))\r \n" ); document.write( "\n" ); document.write( "A= xy -r^2 ( (4-pi)/4)) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |