document.write( "Question 110798: Solve the system by substitution.\r
\n" ); document.write( "\n" ); document.write( "x + y = 12
\n" ); document.write( "y = 2x
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Algebra.Com's Answer #80790 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Start with the given system\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=12\"
\n" ); document.write( "\"y=2x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B%282x%29=12\" Plug in \"y=2x\" into the first equation. In other words, replace each \"y\" with \"2x\". Notice we've eliminated the \"y\" variables. So we now have a simple equation with one unknown.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=12\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"x=4\" Divide both sides by 3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"x=4\", we can plug this into \"y=2x\" to find \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=2%284%29\" Substitute \"4\" for each \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=8\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x=4\" and \"y=8\"
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