document.write( "Question 1178415: A company that supplies ready-mix concrete receives, on average, six orders per
\n" ); document.write( "day.
\n" ); document.write( "(a) What is the probability that, on a given day:
\n" ); document.write( "(i) only one order will be received.
\n" ); document.write( "(ii) no more than three orders will be received.
\n" ); document.write( "(iii) at least three orders will be received.
\n" ); document.write( "(b) What is the probability that, on a given half-day, only one order will be
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Algebra.Com's Answer #807830 by Boreal(15235) $\"\"$ $\"About$

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This is a Poisson distribution with number proportional to time, theoretically could be infinite and mass function.
\n" ); document.write( "P(1)=e^(-6)*6^1/1!=6e^(-6) or 0.0149
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\n" ); document.write( "P(2)=e^(-6)*6^2/2!=0.0446
\n" ); document.write( "P(3)=0.08924
\n" ); document.write( "p(0)=e^(-6)=0.0025
\n" ); document.write( "so P(not greater than 3) is 0.1512 from the calculator rather than adding the four terms above
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\n" ); document.write( "At least 3 means 1-P(0,1,2)=0.9380.
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\n" ); document.write( "A half day is Poisson parameter 3, and the probability of receiving 1 is P(1)=e^(-3)*3^1/1!=3e(-3)=0.1494 \n" ); document.write( "

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