document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1178540>Question 1178540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A new Neighborhood Activity Complex is being built in Oak Valley. The perimeter of the rectangular playing field is 286 yards. The length of the field is 4 yards less than double the width. What are the dimensions of the playing field?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807826 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2W=286 yards<BR>\n" );
document.write( "so L+W=143 yards<BR>\n" );
document.write( "L=2W-4<BR>\n" );
document.write( "so 2W-4+W=143<BR>\n" );
document.write( "3W=147<BR>\n" );
document.write( "Width=49 yards<BR>\n" );
document.write( "Length is 94 yards<BR>\n" );
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