document.write( "Question 1178381: five points O,A,B,C,D are taken in order on a straight line with distances OA=a, OB=b,OC=c,and OD=d.
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document.write( "P is a point on the line between B and C and such that AP:PD=BP:PC.
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document.write( "Find OP in terms of a,b,c,d. \n" );
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Algebra.Com's Answer #807814 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let BP=x. Then \n" ); document.write( "AP = b+x \n" ); document.write( "PD = d-(b+x) \n" ); document.write( "BP = x \n" ); document.write( "PC = c-(b+x) \n" ); document.write( "AP/PD = (b+x)/(d-(b+x)) \n" ); document.write( "BP/PC = x/(c-(b+x)) \n" ); document.write( "AP/PD = BP/PC: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: \n" ); document.write( " \n" ); document.write( " |