document.write( "Question 1178381: five points O,A,B,C,D are taken in order on a straight line with distances OA=a, OB=b,OC=c,and OD=d.
\n" ); document.write( "P is a point on the line between B and C and such that AP:PD=BP:PC.
\n" ); document.write( "Find OP in terms of a,b,c,d.
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Algebra.Com's Answer #807814 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let BP=x. Then

\n" ); document.write( "AP = b+x
\n" ); document.write( "PD = d-(b+x)
\n" ); document.write( "BP = x
\n" ); document.write( "PC = c-(b+x)

\n" ); document.write( "AP/PD = (b+x)/(d-(b+x))

\n" ); document.write( "BP/PC = x/(c-(b+x))

\n" ); document.write( "AP/PD = BP/PC:

\n" ); document.write( "\"%28b%2Bx%29%2F%28d-%28b%2Bx%29%29+=+x%2F%28c-%28b%2Bx%29%29\"

\n" ); document.write( "\"c%28b%2Bx%29-%28b%2Bx%29%5E2+=+dx-bx-x%5E2\"

\n" ); document.write( "\"cb%2Bcx-b%5E2-2bx-x%5E2+=+dx-bx-x%5E2\"

\n" ); document.write( "\"cb%2Bcx-b%5E2-2bx+=+dx-bx\"

\n" ); document.write( "\"cb-b%5E2+=+dx-bx-cx%2B2bx\"

\n" ); document.write( "\"cb-b%5E2+=+bx%2Bdx-cx\"

\n" ); document.write( "\"cb-b%5E2+=+x%28b%2Bd-c%29\"

\n" ); document.write( "\"x+=+%28cb-b%5E2%29%2F%28b%2Bd-c%29\"

\n" ); document.write( "

\n" ); document.write( "ANSWER: \"OP+=+bd%2F%28b%2Bd-c%29\"

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