document.write( "Question 1178503: The pharmacist needs 70 liters of a 55% saline
\n" ); document.write( "solution. The warehouse has barrels of 10% and 80%
\n" ); document.write( "saline solutions. How much of each must she mix to
\n" ); document.write( "fulfill her request?
\n" ); document.write( "

Algebra.Com's Answer #807796 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "People who write math problems are not always well versed in science. Ignore the fact that a 55% saline solution is physically impossible; the purpose of the problem is to give the student practice solving \"mixture\" problems.

\n" ); document.write( "If it makes you feel better, change \"saline solution\" to \"antifreeze solution\" in the statement of the problem....

\n" ); document.write( "(a) Using formal algebra (good practice, if practice with formal algebra is the objective)....

\n" ); document.write( "x liters of 10% solution, plus (70-x) liters of 80% solution, yields 70 liters of 55% solution:

\n" ); document.write( "\".10%28x%29%2B.80%2870-x%29+=+.55%2870%29\"

\n" ); document.write( "Solve using basic algebra; I leave that to you.

\n" ); document.write( "(b) Using a method which is much faster and easier than formal algebra (if the speed of getting the answer is important, and formal algebra is not required)....

\n" ); document.write( "(1) 55% is 45/70 of the way from 10% to 80%. (picture the three percentages 10, 55, and 80 on a number line, if it helps. From 10 to 55 is 45; from 10 to 80 is 70.)
\n" ); document.write( "(2) That means 45/70 of the mixture is the 80% solution.

\n" ); document.write( "ANSWER: 45/70 of 70 liters, or 45 liters, of 80%; the other 25 liters of 10%.

\n" ); document.write( "CHECK:
\n" ); document.write( ".10(25)+.80(45) = 2.5+36 = 38.5
\n" ); document.write( ".55(70) = 38.5

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