document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1061048>Question 1061048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in his report, the cashier of a snack bar turned a number of coins amounting to $6.25 consisting of nickels and dimes. if there were 3 times as many nickels as there were dimes, how many dimes were there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807733 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n = number of nickels<BR>\n" );
document.write( "d = number of dimes\r<BR>\n" );
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document.write( "5n + 10d = 625<BR>\n" );
document.write( "n = 3d\r<BR>\n" );
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document.write( "Substitute the second equation into the first.\r<BR>\n" );
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document.write( "5(3d) + 10d = 625<BR>\n" );
document.write( "25d = 625<BR>\n" );
document.write( "d = 25\r<BR>\n" );
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document.write( "There were 25 dimes. </SPAN>\n" );
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