document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993627>Question 993627</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mandy has 2980 pesos in 1 peso, 5 peso, and 10 peso coins. If she has twice as many 5 peso coins as 1 peso coins and fifty more 10 peso coins than 5 peso coins, how many coins of each type does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807728 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = number of 1 peso coins<BR>\n" );
document.write( "n = number of 5 peso coins<BR>\n" );
document.write( "d = number of 10 peso coins\r<BR>\n" );
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document.write( "p + 5n + 10d = 2980<BR>\n" );
document.write( "n = 2p<BR>\n" );
document.write( "d = n + 50\r<BR>\n" );
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document.write( "Write everything in terms of p.\r<BR>\n" );
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document.write( "p + 5(2p) + 10(2p + 50) = 2980<BR>\n" );
document.write( "p + 10p + 20p + 500 = 2980<BR>\n" );
document.write( "31p = 2480<BR>\n" );
document.write( "p = 80\r<BR>\n" );
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document.write( "Mandy has 80 1-peso coins, 160 5-peso coins, and 210 10-peso coins. </SPAN>\n" );
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