document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993490>Question 993490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Wayne has a collection of 2 cent and 5 cent stamps. He has three times as many 2 cent stamps as 5 cent stamps. The total value is 66 cents. How many stamps does Wayne have?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807718 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = number of 2 cent stamps<BR>\n" );
document.write( "y = number of 5 cent stamps\r<BR>\n" );
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document.write( "x = 3y<BR>\n" );
document.write( "2x + 5y = 66\r<BR>\n" );
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document.write( "Substitute the first equation into the second equation.\r<BR>\n" );
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document.write( "2(3y) + 5y = 66<BR>\n" );
document.write( "11y = 66<BR>\n" );
document.write( "y = 6\r<BR>\n" );
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document.write( "Wayne has 6 five-cent stamps. </SPAN>\n" );
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