document.write( "Question 1053040: Find three numbers such that: their sum is 12;the sum of the first, twice the second, and three times the third is 31;the sum of the third and nine times the second is 1.
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Algebra.Com's Answer #807714 by CubeyThePenguin(3113) You can put this solution on YOUR website! x + y + z = 12 \n" ); document.write( "x + 2y + 3z = 31 \n" ); document.write( "9y + z = 1 ----> z = 1 - 9y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute the expression for z into the first two equations.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y + (1 - 9y) = 12 ---> x - 8y = 11 \n" ); document.write( "x + 2y + 3(1 - 9y) = 31 ---> x - 25y = 28\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract the equations to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 8y = 11 \n" ); document.write( "-x + 25y = -28 \n" ); document.write( "---------------------- \n" ); document.write( "17y = -17 \n" ); document.write( "y = -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9y + z = 1 \n" ); document.write( "9(-1) + z = 1 ---> z = 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + (-1) + 10 = 12 \n" ); document.write( "x = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solution: (x, y, z) = (3, -1, 10) \n" ); document.write( " |