document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060063>Question 1060063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Emma paid the $10.46 bill for her lunch with 242 coins consisting of pennies,nickels,and dimes. if the number of nickles plus the number of dimes was equal to the number of pennies, then how many coins if each type did she use ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807713 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = number of pennies<BR>\n" );
document.write( "n = number of nickels<BR>\n" );
document.write( "d = number of dimes\r<BR>\n" );
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document.write( "p + n + d = 242<BR>\n" );
document.write( "p + 5n + 10d = 1046<BR>\n" );
document.write( "n + d = p\r<BR>\n" );
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document.write( "Write everything in terms of n and d:\r<BR>\n" );
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document.write( "2n + 2d = 242<BR>\n" );
document.write( "6n + 11d = 1046\r<BR>\n" );
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document.write( "Use any method (graphing, substitution, elimination) to solve for n and d, but we will use elimination.\r<BR>\n" );
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document.write( "6n + 6d = 726<BR>\n" );
document.write( "-6n - 11d = -1046<BR>\n" );
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document.write( "-5d = -320<BR>\n" );
document.write( "d = 64 ----> n = 57\r<BR>\n" );
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document.write( "There were 121 pennies, 57 nickels, and 64 dimes. </SPAN>\n" );
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