document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1002940>Question 1002940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You were given $0.65 change using only a total of 5 dimes and quarters combined. how many of each coin are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807691 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807691\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mentally, we see that there are 4 dimes and 1 quarter.\r<BR>\n" );
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document.write( "Algebraically,\r<BR>\n" );
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document.write( "d = number of dimes<BR>\n" );
document.write( "q = number of quarters\r<BR>\n" );
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document.write( "10d + 25q = 65<BR>\n" );
document.write( "d + q = 5\r<BR>\n" );
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document.write( "Multiply the second equation by 10.\r<BR>\n" );
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document.write( "10d + 25q = 65<BR>\n" );
document.write( "-(10d + 10q = 50)<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "15q = 15<BR>\n" );
document.write( "q = 1\r<BR>\n" );
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document.write( "Like before, we have 4 dimes and 1 quarter. </SPAN>\n" );
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