document.write( "Question 1017726: A boy has a total of $.93 in pennies nickels dimes and quarters he has two more quarters and dimes than he has nickels and if he has as many pennies as quarters how many of each coin does he have \n" ); document.write( "
Algebra.Com's Answer #807659 by CubeyThePenguin(3113)\"\" \"About 
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p = number of pennies
\n" ); document.write( "n = number of nickels
\n" ); document.write( "d = number of dimes
\n" ); document.write( "q = number of quarters\r
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\n" ); document.write( "\n" ); document.write( "p + 5n + 10d + 25q = 93
\n" ); document.write( "q = n + 2
\n" ); document.write( "d = n + 2
\n" ); document.write( "p = q\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Write everything in terms of n.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(n + 2) + 5n + 10(n + 2) + 25(n + 2) = 93
\n" ); document.write( "41n + 72 = 93\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The solution to this equation is not an integer, so this situation is not possible.
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