document.write( "Question 1178414: Find the following probabilities using the standard normal z-tables.
\n" ); document.write( "Give a sketch with the appropriate area shaded in.
\n" ); document.write( "(i) P(0 < z < 1.83)
\n" ); document.write( "(ii) P(z > −0.48)
\n" ); document.write( "(iii) P(−2.25 < z < 0)
\n" ); document.write( "(iv) P(1.22 < z)
\n" ); document.write( "(v) P(−2.08 < z < 0.63)
\n" ); document.write( "(vi) P(z < −0.68)
\n" ); document.write( "(vii) P(0.33 < z < 1.5) \n" ); document.write( "
Algebra.Com's Answer #807640 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
document.write( " Using a TI calculator 0r similarly a Casio fx-115 ES plus\r\n" );
document.write( "(i) P(0 < z < 1.83) = normalcdf(0,1.83,0,1) = .4664\r\n" );
document.write( "(ii) P(z > −0.48) = normalcdf(-.48,9999,0,1) = .6844\r\n" );
document.write( "(iii) P(−2.25 < z < 0) = normalcdf(-2.5,0,0,1) = .4938\r\n" );
document.write( "(iv) P(1.22 < z) = normalcdf(-9999,1.22,0,1) = .8888\r\n" );
document.write( "(v) P(−2.08 < z < 0.63) = normalcdf(-2.08,.63,0,1) = .7169\r\n" );
document.write( "(vi) P(z < −0.68) = = normalcdf(-9999,-.68,0,1) = .2483\r\n" );
document.write( "(vii) P(0.33 < z < 1.5) = normalcdf(.33,1.5,0,1) = .3039\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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