Algebra.Com's Answer #807630 by ikleyn(52790)![\"\"](\"/images/stars/stars-13.gif\")  
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document.write( "the  vertices of a triangular base of a truncated prism is defined by A, B, and C.
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document.write( "what is its volume if the length of AB =10 ft, BC = 9ft and CA is 12 ft.
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document.write( "the sides at A, B and C are perpendicular to the triangular base and have the height
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document.write( "of 8.6 ft, 7.1 ft and 5.5 ft, respectively.
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document.write( "The volume of a truncated triangular prim is\r\n" );
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document.write( " V =  ,\r\n" );
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document.write( "where A the area of a right section (the base) and e1, e2 e3 are the lengths of the lateral edges. \r\n" );
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document.write( "So, calculate the base area using the Heron's formula and given base edges 10 ft, 9 ft and 12 ft.\r\n" );
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document.write( "You may use this online calculator\r\n" );
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document.write( "https://keisan.casio.com/exec/system/1223267646\r\n" );
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document.write( "It will give you the base area of 44.039 ft^2.\r\n" );
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document.write( "Then multiply this area by  = 7.066 ft.\r\n" );
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document.write( "You will get the volume of your truncated prism of V = 44.039 * 7.066 = 311.17 ft^3. ANSWER\r\n" );
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document.write( "Solved.\r
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