document.write( "Question 1178369: the area of a triangular lot is 2,598.08 m^2. if the sides of the lot are in continued proportion of 3:5:7 , find the shortest side of the lot. \n" ); document.write( "
Algebra.Com's Answer #807587 by amarjeeth123(570)\"\" \"About 
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The sides of the lot are in the proportion of 3:5:7.
\n" ); document.write( "Let the sides be 3x,5x and 7x where x is a constant.
\n" ); document.write( "Let the sides be a=3x, b=5x and c=7x where a,b and c are the three sides.
\n" ); document.write( "Area of a triangle=\"sqrt%284%2Aa%5E2%2Ab%5E2-%28a%5E2%2Bb%5E2-c%5E2%29%5E2%29%2F4\"
\n" ); document.write( "Plugging in the values we get,
\n" ); document.write( "Area of the triangle=\"sqrt%284%2Aa%5E2%2Ab%5E2-%28a%5E2%2Bb%5E2-c%5E2%29%5E2%29%2F4\"=sqrt(675)*(x^2/4)
\n" ); document.write( "Area of the triangle=2,598.08 m^2
\n" ); document.write( "Equating both sides we get,
\n" ); document.write( "sqrt(675)*(x^2/4)=2,598.08 m^2
\n" ); document.write( "x^2=(2598.08*4)/sqrt(675)
\n" ); document.write( "x^2=400.0005
\n" ); document.write( "x=sqrt(400.0005)=20
\n" ); document.write( "The value of x is 20.
\n" ); document.write( "The shortest side of the lot is 3x which is 60m.
\n" ); document.write( "Answer=60m. \n" ); document.write( "
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