document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1178299>Question 1178299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the length of LK\r<BR>\n" );
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document.write( "LJ=3x-2<BR>\n" );
document.write( "LK= 2x<BR>\n" );
document.write( "KM=10<BR>\n" );
document.write( "MJ=12.5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807504 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LK +KJ+JM = LJ\r<BR>\n" );
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document.write( "2x+10+12.5 = 3x-2\r<BR>\n" );
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document.write( "x=24.5\r<BR>\n" );
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document.write( "LK =2x = 45 </SPAN>\n" );
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