document.write( "Question 1178287: Use the given zero to find all other zeros.
\n" ); document.write( "Zero:2i
\n" ); document.write( "Equation: F(x)=2x^3+3x^2+8x+12
\n" ); document.write( "Thanks in advance! \n" ); document.write( "

Algebra.Com's Answer #807482 by josgarithmetic(39625) $\"\"$ $\"About$

You can put this solution on YOUR website!
Quadratic factor of F is

. Use this to help find your other two zeros. Try polynomial division or whatever other method you find helpful.\r
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document.write( "              2x    3\r\n" );
document.write( "          ______________________________\r\n" );
document.write( "x^2+0x+4  |   2x^3 +3x^2  + 8x + 12\r\n" );
document.write( "          |   2x^3 + 0x^2 + 8x\r\n" );
document.write( "          |   -----------------\r\n" );
document.write( "               0    3x^2   0x   12\r\n" );
document.write( "                    3x^2   0x   12\r\n" );
document.write( "                   ----------------\r\n" );
document.write( "                     0     0    0\r\n" );
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\n" ); document.write( "The zero found here, $\"2x%2B3\"$ for $\"x=-3%2F2\"$ .\r
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\n" ); document.write( "\n" ); document.write( "Or this could work too:
\n" ); document.write( " $\"2x%5E3%2B8x%2B3x%5E2%2B12\"$
\n" ); document.write( " $\"2%28x%5E3%2B4x%29%2B3%28x%5E2%2B4%29\"$
\n" ); document.write( " $\"2x%28x%5E2%2B4%29%2B3%28x%5E2%2B4%29\"$
\n" ); document.write( " $\"%28x%5E2%2B4%29%282x%2B3%29\"$ ----------and the other zero is $\"-3%2F2\"$ . \n" ); document.write( "

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