document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110772>Question 110772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help? This take home exercise has me stumped:\r<BR>\n" );
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document.write( "Write the quadratic equation, given the solution: (3/5, 2/7)\r<BR>\n" );
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document.write( "Thank you.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80746 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do things backwards.<BR>\n" );
document.write( "x=3/5, x=2/7<BR>\n" );
document.write( "(x-(3/5))(x-(2/7))=0<BR>\n" );
document.write( "x^2-(3x/5)-(2x/7)+(6/35)=0<BR>\n" );
document.write( "-(3/5)-(2/7)=-(21/35)-(10/35)=-31/35<BR>\n" );
document.write( "x^2-(31x/35)+(6/35)=0<BR>\n" );
document.write( "Ed </SPAN>\n" );
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