document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1178200>Question 1178200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What nominal rate of interest compounded quarterly is needed to triple a principle in 9 years? (Round your answer to 2 decimal places)\r<BR>\n" );
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document.write( "A=P(1+r)^t<BR>\n" );
document.write( "4=1(1+r)^9<BR>\n" );
document.write( "4=1+r^9<BR>\n" );
document.write( "4-1=r^9<BR>\n" );
document.write( "3=r^9\r<BR>\n" );
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document.write( "I saw this formula online: A=P(1+r)^t. I saw that there are similar problems posted on this site, and I see that they use \"log,\" but I can not find an example that shows the complete steps. Also, do you have to use log to solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807384 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "A=P(1+r)^nt\r<BR>\n" );
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document.write( "simplify\r<BR>\n" );
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document.write( "r = n[(A/P)1/nt - 1]\r<BR>\n" );
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document.write( "r = 4 × [(300.00/100.00)1/(4)(9) - 1]<BR>\n" );
document.write( "r = 0.1239496\r<BR>\n" );
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document.write( "=12.39%\r<BR>\n" );
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document.write( " </SPAN>\n" );
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