document.write( "Question 110756: A small company produces both bouquets and wreaths of dried flowers. The bouquets take 1 hr of labor to produce and the wreaths take 2 hrs. The labor available is limited to 80 hrs per wk and the total production capacity is 60 items per week. Write a system of inequalities representing this situation, where x is the number of bouquets and y is the number of wreaths. Then graph the system of inequalities.\r
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Algebra.Com's Answer #80737 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
(bouquets)(hrs per bouquet) + (wreaths)(hrs per wreath) < 80 (per week)
\n" ); document.write( "x*1 + y*2 < 80
\n" ); document.write( " $\"x+%2B+2y+%3C=+80\"$
\n" ); document.write( " $\"2y+%3C=+-x+%2B+80\"$
\n" ); document.write( " $\"y+%3C=+-%281%2F2%29x+%2B+40\"$ answer
\n" ); document.write( "(bouquets) + (wreaths) < = 60 items (per week)
\n" ); document.write( " $\"x+%2B+y+%3C=+60\"$
\n" ); document.write( " $\"y+%3C=+-x+%2B+60\"$ answer
\n" ); document.write( " $\"+graph%28+500%2C+500%2C+-10%2C+90%2C+-10%2C+80%2C-%281%2F2%29x+%2B+40%2C-x+%2B+60%29+\"$
\n" ); document.write( "The vertical axis is number of wreaths and hours per week working
\n" ); document.write( "on wreaths
\n" ); document.write( "The horizontal axis is number of bouquets and hours per week working on
\n" ); document.write( "bouquets
\n" ); document.write( "The operating area is under BOTH lines
\n" ); document.write( "If I solve
\n" ); document.write( " $\"y+=+-%281%2F2%29x+%2B+40\"$
\n" ); document.write( " $\"y+=+-x+%2B+60\"$
\n" ); document.write( "subtract the 2nd from the 1st
\n" ); document.write( " $\"%281%2F2%29x+-20\"$ = 0
\n" ); document.write( " $\"x+=+40\"$
\n" ); document.write( " $\"y+=+20\"$
\n" ); document.write( "This is the point where the lines meet \n" ); document.write( "

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