document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1178163>Question 1178163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3m less than twice the width, and the area of the rectangle is 14m^2 . Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807331 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be x <BR>\n" );
document.write( "length 2x-3\r<BR>\n" );
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document.write( "Area = Length * width<BR>\n" );
document.write( "x(2x-3) =14<BR>\n" );
document.write( "2x^2-3x =14\r<BR>\n" );
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document.write( "2x^2-3x-14=0\r<BR>\n" );
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document.write( "2x^2-7x+4x-14 =0\r<BR>\n" );
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document.write( "x(2x-7) +2(2x-7)=0\r<BR>\n" );
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document.write( "(2x-7)(x+2)=0\r<BR>\n" );
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document.write( "x=7/2 OR -2<BR>\n" );
document.write( "ignore negative\r<BR>\n" );
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document.write( "width = 3.5 m\r<BR>\n" );
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document.write( "length = 2x-3 = 2*7/2  -3 =4<BR>\n" );
document.write( "Length = 4 m\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );