document.write( "Question 1178160: Solve the equation for solutions in the interval 0 ≤ x < 2𝜋. Round approximate solutions to the nearest ten-thousandth. \r
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document.write( "4 sin^3 x = sin x \n" );
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Algebra.Com's Answer #807329 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! this is 4sin^3x-sin x=0 \n" ); document.write( "sin x(4 sin^2x-1)=0=sin x(2 sin x+1)(2 sin x-1) \n" ); document.write( "x=0 degrees \n" ); document.write( "x=30 and 150 degrees \n" ); document.write( "x=210 and 330 degrees; graph in radians\r \n" ); document.write( "\n" ); document.write( " |