document.write( "Question 1178159: Solve the equation for solutions in the interval 0 ≤ x < 2𝜋. Round approximate solutions to the nearest ten-thousandth. \r
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document.write( "2 sin^2 x − 1 = 0 \n" );
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Algebra.Com's Answer #807328 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 2sin^2(x)=1 \n" ); document.write( "sin^2(x)=(1/2) \n" ); document.write( "sin(x)=+/- sqrt(2)/2=+/-0.7071 \n" ); document.write( "this is 45,135,225,315 degrees \n" ); document.write( " \n" ); document.write( " |