document.write( "Question 1178161: Solve the equation, where 0° ≤ x < 360°.\r
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document.write( "2 sin^2 x = 1 − cos x \n" );
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Algebra.Com's Answer #807327 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! sin^2 x=1-cos^2 x \n" ); document.write( "so 2-2cos^2x=1-cos x \n" ); document.write( "0=2 cos^2 x-cos x -1 \n" ); document.write( "0=(2 cos x+1)(cos x-1) \n" ); document.write( "cos x =-0.5 \n" ); document.write( "cos x=+1 \n" ); document.write( "x=0 degrees, 120 degrees, 240 degrees \n" ); document.write( " |