document.write( "Question 1178161: Solve the equation, where 0° ≤ x < 360°.\r
\n" ); document.write( "\n" ); document.write( "2 sin^2 x = 1 − cos x
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Algebra.Com's Answer #807327 by Boreal(15235)\"\" \"About 
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sin^2 x=1-cos^2 x
\n" ); document.write( "so 2-2cos^2x=1-cos x
\n" ); document.write( "0=2 cos^2 x-cos x -1
\n" ); document.write( "0=(2 cos x+1)(cos x-1)
\n" ); document.write( "cos x =-0.5
\n" ); document.write( "cos x=+1
\n" ); document.write( "x=0 degrees, 120 degrees, 240 degrees
\n" ); document.write( "\"graph%28300%2C300%2C-6%2C6%2C-1%2C2%2C2sin%28x%29%5E2%2Bcos%28x%29-1%29\"
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