document.write( "Question 110617: Describe the roots of the equation: 7x^2 + 2x - 3 = 0 \n" ); document.write( "
Algebra.Com's Answer #80732 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"7%2Ax%5E2%2B2%2Ax-3=0\" ( notice \"a=7\", \"b=2\", and \"c=-3\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+%282%29%5E2-4%2A7%2A-3+%29%29%2F%282%2A7%29\" Plug in a=7, b=2, and c=-3\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4-4%2A7%2A-3+%29%29%2F%282%2A7%29\" Square 2 to get 4 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4%2B84+%29%29%2F%282%2A7%29\" Multiply \"-4%2A-3%2A7\" to get \"84\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+88+%29%29%2F%282%2A7%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+2%2Asqrt%2822%29%29%2F%282%2A7%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B-+2%2Asqrt%2822%29%29%2F14\" Multiply 2 and 7 to get 14\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-2+%2B+2%2Asqrt%2822%29%29%2F14\" or \"x+=+%28-2+-+2%2Asqrt%2822%29%29%2F14\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2%2F14%2B2%2Asqrt%2822%29%2F14\" or \"x=-2%2F14-2%2Asqrt%2822%29%2F14\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-1+%2F+7%2Bsqrt%2822%29%2F7\" or \"x=-1+%2F+7-sqrt%2822%29%2F7\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=0.527202251403347\" or \"x=-0.812916537117633\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=0.527202251403347\" or \"x=-0.812916537117633\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"7%2Ax%5E2%2B2%2Ax-3\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=0.527202251403347\" and \"x=-0.812916537117633\".So this verifies our answer\r
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