document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1178132>Question 1178132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Given:AB=(3x-5)cm,BC=(2y-7)cm,CD=(X+7)cm and AD=(y+3)cm.<BR>\n" );
document.write( "a.what is the value of x?<BR>\n" );
document.write( "b.how long is AB?<BR>\n" );
document.write( "c.what is the value of y?<BR>\n" );
document.write( "d.how long is AD?<BR>\n" );
document.write( "e.how did you solve for the values of x and y?<BR>\n" );
document.write( "f.what property did you apply to determine the lengths of AB and AD?\r<BR>\n" );
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document.write( "2.BAD measures (2a+25)° while BCD measures (3a-15)°<BR>\n" );
document.write( "a.what is the value of a?<BR>\n" );
document.write( "b.what is the m BAD<BR>\n" );
document.write( "c.what is the m CBA?<BR>\n" );
document.write( "e.how did you find the value of a?<BR>\n" );
document.write( "f.what property did you apply to solve for m CBA? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #807295 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=807295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Given:AB=(3x-5)cm,BC=(2y-7)cm,CD=(X+7)cm and AD=(y+3)cm.\r<BR>\n" );
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document.write( "AB=CD, BC =AD opposite sides of parallelogram<BR>\n" );
document.write( "AB=(3x-5)cm,BC=(2y-7)cm,CD=(X+7)cm and AD=(y+3)cm.\r<BR>\n" );
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document.write( "(3x-5)=(X+7) .<BR>\n" );
document.write( "2x=12<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "a.what is the value of x? x=6<BR>\n" );
document.write( "b.how long is AB?<BR>\n" );
document.write( "AB=3x-5 = 13\r<BR>\n" );
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document.write( "c.what is the value of y?<BR>\n" );
document.write( "2y-7 =y+3<BR>\n" );
document.write( "y=10<BR>\n" );
document.write( "d.how long is AD? y+3 . AD=13<BR>\n" );
document.write( "e.how did you solve for the values of x and y?<BR>\n" );
document.write( "f.what property did you apply to determine the lengths of AB and AD?<BR>\n" );
document.write( "AB=CD, BC =AD opposite sides of parallelogram\r<BR>\n" );
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document.write( "2.BAD measures (2a+25)° while BCD measures (3a-15)°<BR>\n" );
document.write( "(2a+25)° =(3a-15)°<BR>\n" );
document.write( "a=40 deg\r<BR>\n" );
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document.write( "a.what is the value of a? 40 deg<BR>\n" );
document.write( "b.what is the m BAD = 2a +25 =105 deg\r<BR>\n" );
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document.write( "c.what is the m CBA?<BR>\n" );
document.write( "m CBA = 75 deg<BR>\n" );
document.write( "e.how did you find the value of a?<BR>\n" );
document.write( "mBAD + mA CBA=180 deg <BR>\n" );
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document.write( "f.what property did you apply to solve for m CBA?<BR>\n" );
document.write( "Adjacent angles of a parallelogram are supplementary </SPAN>\n" );
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