document.write( "Question 1178093: Rose makes an investment worth Php 15,000 in a savings bank paying 14% compounded monthly. If she withdraws all her investments and the interest with amounts to Php 19, 450,how long did she invest her money? \n" ); document.write( "
Algebra.Com's Answer #807249 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the formula to use is f = p * (1 + r) ^ n \n" ); document.write( "f is the future value \n" ); document.write( "p is the present value \n" ); document.write( "r is the interest rate per time period \n" ); document.write( "n is the number of time periods.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in your problem:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f = 19450 \n" ); document.write( "p = 15000 \n" ); document.write( "r = 14% / 100 = .14 / 12 = .01166666667 per month. \n" ); document.write( "n = the number of months you want to find.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes 19450 = 15000 * (1 + .01166666667) ^ n\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 15000 to get: \n" ); document.write( "19450/15000 = (1 + .01166666667) ^ n \n" ); document.write( "take the log of both sides of the equation to get: \n" ); document.write( "log(19450/15000) = log((1 + .01166666667) ^ n) \n" ); document.write( "since log(x^n) = n * log(x), this becomes: \n" ); document.write( "log(19450/15000) = n * log(1.01166666667) \n" ); document.write( "divide both sides of the equation by log(1.01166666667) to get: \n" ); document.write( "log(19450/15000) / log(1.01166666667) = n \n" ); document.write( "solve for n to get: \n" ); document.write( "n = 22.39795036 months.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "confirm this is correct by replacing n in the original equation with that to get: \n" ); document.write( "f = 15000 * (1 + .01166666667) ^ 22.39795036 = 19450.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this confirms the solution is correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the solution is 22.39795036 months for 15000 to grow to 19450 at 14% interest per year compounded monthly.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you could also have used an online financial calculator to get the same results.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here are the inputs to that calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here is the output from that calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the calculator uses the percent rather than the rate. \n" ); document.write( "the calculator rounds the answer to 2 decimal places.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |