document.write( "Question 1178012: The coordinates of the point P,Q,R are (-1,11),(2,5) and (t,3) respectively. Given that ∠PQR = 90 °, calculate the value of t. The line PQ is produced to S so that QS = PQ. Calculate the coordinates of S. \n" ); document.write( "
Algebra.Com's Answer #807206 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Part 1: find t. \n" ); document.write( "From P to Q is 3 units right and 6 units down; the slope of PQ is -2. \n" ); document.write( "PQR is a right angle, so the slope of QR is +1/2. That means on QR the change in y is 1/2 the change in x -- i.e., the change in x is 2 times the change in y. \n" ); document.write( "From Q to R the change in y is -2, so the change in x has to be -4. A change of -4 in x and a change of -2 in y from Q(2,5) puts us at R(-2,3). \n" ); document.write( "ANSWER: t = -2. \n" ); document.write( "Part 2: Find the coordinates of point S. \n" ); document.write( "S is on PQ extended, and QS = PQ. \n" ); document.write( "From P to Q was 3 units right and 6 units down; from Q to S will be the same. \n" ); document.write( "3 right and 6 down from Q(2,5) puts us at S(5,-1). \n" ); document.write( "ANSWER: S is (5,-1). \n" ); document.write( " \n" ); document.write( " |