document.write( "Question 1177993: In an all boys school, the heights of the student body are normally distributed with a mean of 67 inches and a standard deviation of 4.5 inches. Using the empirical rule, determine the interval of heights that represents the middle 68% of male heights from this school. \n" ); document.write( "
Algebra.Com's Answer #807181 by Theo(13342)![]() ![]() You can put this solution on YOUR website! here's a definition of the empirical rule.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "https://www.investopedia.com/terms/e/empirical-rule.asp\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "based on that rule, 6% are wihin 1 standard deviation of the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the mean is 67 and the standrd deviation is 4.5 inches, then the interval of heights that represents the middle 68% of male heights from the school will be:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "62.5 inches to 71.5 inches.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "heare are two displays that show this to be true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first display looks for the area from a value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the second display looks for the value from an area.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |